Alcohols and Phenols
Alcohols (R–OH) and phenols (Ar–OH) both carry a hydroxyl group, yet their reactivity differs sharply because of the aromatic ring in phenol. The PMDC MDCAT 2026 syllabus expects you to compare the two classes, name and draw their structures, and master high-yield reactions such as the Lucas test, Williamson synthesis, and the acidity comparison. Expect 2–3 MCQs from this chapter.
Difference between Alcohol and Phenol
Both classes contain a hydroxyl group, but in alcohols the –OH is attached to an sp3 carbon of an aliphatic chain, whereas in phenol the –OH is bonded directly to an sp2 carbon of a benzene ring. This single structural difference governs every chemical contrast between them.
- Alcohol
- A compound in which –OH is bonded to a saturated sp3 carbon. General formula R–OH. Example: CH3CH2OH (ethanol).
- Phenol
- A compound in which –OH is bonded directly to a benzene ring. General formula Ar–OH. Example: C6H5OH (carbolic acid).
Side-by-side comparison
| Property | Alcohol (R–OH) | Phenol (Ar–OH) |
|---|---|---|
| C–OH carbon | sp3 (aliphatic) | sp2 (aromatic ring) |
| Example | CH3CH2OH (ethanol) | C6H5OH (carbolic acid) |
| Acidity (pKa) | ~16–18 (weaker than water) | ~10 (stronger than water, weaker than COOH) |
| Reaction with NaOH | No reaction | Forms sodium phenoxide (salt) |
| Reaction with NaHCO3 | No reaction | No reaction (too weak to liberate CO2) |
| Reaction with Na metal | Yes — gives RONa + H2↑ | Yes — gives ArONa + H2↑ |
| FeCl3 test | No colour | Violet / purple complex |
| Lucas test (ZnCl2/HCl) | Distinguishes 1° / 2° / 3° alcohols | Not applicable |
| Esterification with RCOOH | Easy | Slower (less nucleophilic O) |
| Conjugate base stability | Alkoxide RO− — no resonance | Phenoxide — stabilised by resonance over o, p ring carbons |
| Aromatic ring substitution | N/A | Highly reactive at o, p positions (ring activator) |
Nomenclature, Structure and Reactivity of Alcohols
Alcohols are classified by the number of carbons attached to the carbon bearing the –OH group. The chemistry of an alcohol is dominated by two reactive sites: the polar O–H bond and the C–O bond.
IUPAC nomenclature
- Choose the longest carbon chain that contains the –OH group.
- Replace the parent alkane suffix –e with –ol (e.g. methane → methanol).
- Number the chain to give the carbon bearing the –OH the lowest locant.
- Examples: CH3OH = methanol, CH3CH2OH = ethanol, (CH3)2CHOH = propan-2-ol, (CH3)3COH = 2-methylpropan-2-ol.
Classification
- Primary (1°)
- –OH on a carbon bonded to one other carbon. Example: ethanol CH3CH2OH.
- Secondary (2°)
- –OH on a carbon bonded to two other carbons. Example: propan-2-ol (CH3)2CHOH.
- Tertiary (3°)
- –OH on a carbon bonded to three other carbons. Example: 2-methylpropan-2-ol (CH3)3COH.
Physical properties
Alcohols form intermolecular hydrogen bonds, so their boiling points are markedly higher than those of comparable alkanes or ethers. Lower alcohols (C1–C3) are completely miscible with water; solubility falls off as the hydrocarbon tail lengthens.
Reactions of alcohols
2 R–OH + 2 Na → 2 R–ONa + H2↑. Sodium displaces the hydroxylic hydrogen to give a sodium alkoxide and hydrogen gas. The reaction is slower than that of water.
R–OH + HX → R–X + H2O. Reactivity order of HX: HI > HBr > HCl. Reactivity order of alcohols: 3° > 2° > 1° (because tertiary carbocations are more stable in the SN1 pathway).
Reagent: anhydrous ZnCl2 in concentrated HCl.
3° alcohol → turbidity immediately.
2° alcohol → turbidity in 5–10 minutes.
1° alcohol → no turbidity at room temperature.
R–CH2–CH2–OH ⟶{conc. H2SO4, 170°C} R–CH=CH2 + H2O. Ease of dehydration: 3° > 2° > 1°. Mechanism: E1 (3°, 2°) or E2 (1°). Follows Saytzeff's rule — the more substituted alkene is the major product.
1° alcohol ⟶{[O], KMnO4 or K2Cr2O7} aldehyde ⟶{[O]} carboxylic acid.
2° alcohol ⟶{[O]} ketone (no further oxidation under mild conditions).
3° alcohol — not oxidised under normal conditions (no α-H attached to C–OH).
R–OH + R′COOH ⟶{conc. H2SO4} R′COOR + H2O. Reversible; driven forward by removing water.
R–ONa + R′–X → R–O–R′ + NaX. The sodium alkoxide attacks the alkyl halide via SN2; works best with 1° halides — tertiary halides give elimination instead.
Nomenclature, Structure and Reactivity of Phenols
Phenol, C6H5OH, was the first commercial antiseptic (Joseph Lister, 1865). Modern uses include resin manufacture (Bakelite) and aspirin synthesis. The aromatic ring activates strongly toward electrophilic substitution and stabilises the conjugate base.
IUPAC nomenclature
- The parent is "phenol" (retained IUPAC name) or "benzenol".
- Substituents are numbered such that –OH is C-1.
- Common examples: 2-methylphenol (o-cresol), 4-nitrophenol, 2,4,6-trinitrophenol (picric acid), 1,2-dihydroxybenzene (catechol), 1,3-dihydroxybenzene (resorcinol), 1,4-dihydroxybenzene (hydroquinone).
Structure and bonding
The oxygen is sp2-hybridised and donates a lone pair into the π system, increasing electron density at the ortho and para positions. This makes phenol an activating, ortho/para-directing substrate in electrophilic aromatic substitution and explains its higher acidity relative to alcohols.
Acidity of phenol
Phenol pKa ≈ 10 vs ethanol pKa ≈ 16. Reasons: (i) the phenoxide negative charge is delocalised over the ring; (ii) the C–O bond has partial double-bond character. Electron-withdrawing groups (–NO2, –CN, –X) at ortho/para positions further increase acidity — picric acid (2,4,6-trinitrophenol) has pKa ~ 0.4 and is as strong as a mineral acid.
Reactions of phenol
C6H5OH + NaOH → C6H5ONa + H2O. Phenol is acidic enough to dissolve in dilute NaOH — alcohols are not. (Distinguishing test.)
Phenols give a deep violet/purple colour with neutral aqueous FeCl3. Alcohols give no colour. Diagnostic test for phenolic –OH.
C6H5OH + 3 Br2 (aq) → 2,4,6-tribromophenol (white precipitate) + 3 HBr. No catalyst needed — the ring is so activated that all three ortho/para positions are attacked at once.
Dilute HNO3 at low temperature gives a mixture of o- and p-nitrophenol. Concentrated HNO3 with H2SO4 drives full substitution to picric acid (2,4,6-trinitrophenol).
Sodium phenoxide + CO2 at 125°C/4–7 atm, then acid, gives salicylic acid (2-hydroxybenzoic acid) — the precursor of aspirin.
Phenol + CHCl3 + NaOH → salicylaldehyde (2-hydroxybenzaldehyde) on acidic workup. Introduces an –CHO group ortho to the –OH.
Worked MCQs
Five MCQs that capture the high-yield testing patterns for this chapter. Read the explanation even when you get the answer right — that's where the deeper concept lives.
Q1. The Lucas reagent (anhydrous ZnCl2 in concentrated HCl) reacts immediately with which of the following?
2-methylpropan-2-ol is a tertiary alcohol; it forms a stable 3° carbocation that captures Cl− at once, producing an immediate cloudiness. Secondary alcohols take 5–10 minutes; primary alcohols give no turbidity at room temperature.
Q2. Phenol is more acidic than ethanol primarily because:
When phenol loses a proton, the resulting negative charge is delocalised over the ortho and para ring carbons. This resonance stabilisation lowers the energy of the phenoxide ion, shifting the ionisation equilibrium far to the right relative to ethanol.
Q3. Which alcohol cannot be oxidised by acidified K2Cr2O7 under normal conditions?
A tertiary alcohol has no α-hydrogen on the carbon bearing the –OH, so the C–H bond required for oxidation is absent. Primary alcohols oxidise to acids and secondary alcohols to ketones; tertiary alcohols resist oxidation unless very harsh conditions break the C–C skeleton.
Q4. Phenol on reaction with excess bromine water gives:
The ring in phenol is so strongly activated by the –OH that no Lewis-acid catalyst is required. All three ortho/para positions are brominated simultaneously, precipitating white 2,4,6-tribromophenol from solution.
Q5. The Williamson ether synthesis works best with:
Williamson synthesis proceeds via SN2: the alkoxide is a strong nucleophile/base and 1° halides have the least steric hindrance. With 3° halides, the alkoxide acts as a base instead, giving alkene by E2.
Quick Recap
- Alcohol: –OH on sp3 C; phenol: –OH on sp2 C of an aromatic ring.
- Acidity: carboxylic acid > phenol > water > alcohol.
- Lucas test: 3° instant, 2° in minutes, 1° no reaction.
- Oxidation: 1° → aldehyde → acid; 2° → ketone; 3° → no reaction.
- Williamson ether synthesis prefers 1° halides (SN2).
- Phenol gives violet colour with FeCl3; dissolves in NaOH (alcohols don't).
- Phenol + 3 Br2 (aq) → 2,4,6-tribromophenol; Kolbe–Schmitt → salicylic acid (aspirin precursor).