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Organic Chemistry Fundamentals

Organic chemistry is the chemistry of carbon compounds. Although it is a small section of the PMDC MDCAT 2026 syllabus, it underpins every chapter that follows — hydrocarbons, alkyl halides, alcohols, aldehydes, carboxylic acids and macromolecules. Master the basics here (hybridisation, IUPAC, reaction types, reactive intermediates) and the rest of organic chemistry becomes pattern recognition rather than memorisation.

PMC Table of Specifications. The single PMDC subtopic for this chapter is "Definition and Classification of Organic Compounds", but the syllabus expects fluency with hybridisation, IUPAC numbering, homologous series, reaction types, and reactive intermediates — all covered below.

Definition and Classification of Organic Compounds

Organic chemistry is the branch of chemistry dealing with compounds of carbon, except for a few exceptions traditionally classed as inorganic (oxides of carbon, carbonates, bicarbonates, cyanides, carbides). Carbon's unique properties — tetravalency, small size, and the ability to catenate (bond to itself in long chains and rings) — allow it to form millions of compounds.

Hybridisation in carbon

The ground state of carbon is 1s2 2s2 2p2, but in compounds carbon is always tetravalent. To explain this, one 2s electron is promoted to a 2p orbital and the resulting orbitals mix (hybridise).

Sigma (σ) and pi (π) bonds in carbon

IUPAC numbering rules (basic)

  1. Find the longest continuous carbon chain containing the principal functional group — this is the parent chain.
  2. Number the chain so the principal functional group (or, if absent, the first substituent) gets the lowest possible locant.
  3. List substituents alphabetically (ignoring di-, tri-, tetra- prefixes).
  4. For double/triple bonds, assign the lower locant to the multiple bond (suffix –ene, –yne).
  5. If two numbering schemes give the same lowest locant for the suffix, choose the one giving the lowest locant to the substituent at the first point of difference (the "lowest set of locants" rule).

Homologous series

A homologous series is a family of organic compounds with the same general formula, the same functional group, and consecutive members differing by a –CH2 unit (relative molar mass differs by 14). Members show a gradual change in physical properties (melting point, boiling point, density) and similar chemical properties.

Classification of organic compounds

Types of organic reactions

Addition
Two molecules combine to give one product, with the breaking of a π bond. Typical of alkenes and alkynes. Example: CH2=CH2 + Br2 → CH2Br–CH2Br.
Elimination
The reverse of addition — one molecule splits into two, generating a π bond. Example: dehydration of ethanol over hot Al2O3 → CH2=CH2 + H2O.
Substitution
An atom or group is replaced by another. Typical of alkanes and aromatics. Example: CH4 + Cl2 (hν) → CH3Cl + HCl. Subtypes: SN1, SN2, SE (electrophilic substitution in benzene).
Rearrangement
Atoms within a molecule reorganise to give a structural isomer of the starting material. Example: 1-butene ⇌ 2-butene under acid catalysis; carbocation rearrangements (1,2-H or 1,2-CH3 shifts).

Reactive intermediates — electrophiles, nucleophiles, free radicals

Electrophile (E+)
"Electron-loving" species; electron-deficient; accepts an electron pair to form a new bond. Examples: H+, NO2+, SO3, Br+, AlCl3, carbocations (R3C+).
Nucleophile (Nu:)
"Nucleus-loving" species; electron-rich; donates a lone pair to form a new bond. Examples: OH, CN, NH3, H2O, Cl, R (carbanions).
Free radical (R·)
Species with an unpaired electron; formed by homolytic bond fission (each atom keeps one electron). Highly reactive. Generated by UV light or peroxides. Drive chain mechanisms in halogenation of alkanes and combustion.

Bond breaking patterns:

Common trap. A π bond is not a separate bond independent of σ. A double bond (1σ + 1π) is one bond unit with two pairs of electrons; the π component is weaker, breaks more easily, and is the reason alkenes are more reactive than alkanes despite having a "stronger" overall bond.
Memory aid. "sp3 = single, sp2 = double, sp = triple." The number of un-hybridised p orbitals (0, 1, 2) tells you how many π bonds the carbon can form, and therefore the bond order to its partner.

Worked MCQs

Five MCQs that capture the high-yield testing patterns for this chapter. Read the explanation even when you get the answer right — it's where the deeper concept lives.

Q1. The hybridisation of each carbon atom in ethyne (C2H2) is:

  • sp3
  • sp2
  • sp
  • sp3d

In ethyne the C≡C triple bond is made of one σ bond and two π bonds. Each carbon uses two sp hybrid orbitals (linear, 180°) for σ bonds and the two un-hybridised p orbitals for the two π bonds.

Q2. Which of the following is NOT a feature of a homologous series?

  • Same general formula
  • Same functional group
  • Successive members differ by –CH2
  • Identical physical properties

Members of a homologous series share chemical properties because they share a functional group, but their physical properties (boiling point, melting point, density) change gradually with chain length — they are not identical.

Q3. Which species is best described as a nucleophile?

  • NO2+
  • AlCl3
  • CN
  • H+

A nucleophile is electron-rich and donates a lone pair. CN has a negative charge and lone pairs on both C and N, so it readily attacks electrophilic carbons. NO2+, AlCl3, and H+ are all electrophiles.

Q4. The reaction CH4 + Cl2 → CH3Cl + HCl (in UV light) is best classified as:

  • Electrophilic addition
  • Nucleophilic substitution
  • Free-radical substitution
  • Elimination

UV light causes homolytic fission of Cl–Cl into two Cl· radicals. These abstract H from CH4 in a chain mechanism, replacing one H by Cl. It is therefore a substitution reaction proceeding by a free-radical mechanism.

Q5. A double bond between two carbon atoms consists of:

  • Two σ bonds
  • One σ bond and one π bond
  • Two π bonds
  • One σ bond and two π bonds

Every covalent bond between two atoms includes exactly one σ bond. The remaining bonds beyond that σ are π bonds: a double bond is 1σ + 1π, a triple bond is 1σ + 2π.

Quick Recap

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