Atomic Spectra
When an atom emits or absorbs light it does so only at sharply defined wavelengths — producing a line spectrum rather than a continuous one. The PMDC MDCAT 2026 syllabus reduces this chapter to a single subtopic with one learning outcome: describe and explain atomic spectra / line spectrum. Expect 1-2 high-yield MCQs.
Atomic Spectra and Line Spectrum
A spectrum is the range of EM wavelengths emitted or absorbed by a substance. Hot solids emit a continuous spectrum; rarefied gases excited by an electric discharge emit a line emission spectrum — a set of bright lines on a dark background. A cool gas placed between a continuous source and a spectrometer absorbs the same wavelengths, producing a line absorption spectrum (dark lines on bright background, e.g. Fraunhofer lines in sunlight).
Why the spectrum is a set of lines
An atom can only possess certain discrete amounts of internal energy — its energy levels. The atom cannot hold an energy between two levels.
- When an electron drops from a higher level of energy Ei to a lower level Ef, the surplus energy leaves as a single photon: hf = Ei − Ef.
- Because only certain energy differences are possible, only certain frequencies (and therefore wavelengths) can be emitted — so the spectrum is a set of sharp lines, not a continuous band.
- Every element has its own unique set of energy levels, so its line spectrum is a fingerprint used to identify the element in a source such as a star or a flame.
A hot, dense source (a glowing filament, molten metal, the Sun's interior) emits all wavelengths — a continuous spectrum with no gaps. A low-pressure gas of free atoms emits only the wavelengths allowed by its energy-level differences — a line spectrum. The difference is the state of the source, not the type of light.
Emission vs absorption spectra
- Emission: excited atom drops from a higher to a lower level, releasing a photon. Bright line on dark background.
- Absorption: a cool gas absorbs photons of specific wavelengths from a continuous source, lifting electrons to higher levels. Dark line on bright background.
- Both spectra share the same wavelengths for a given element — a chemical fingerprint.
Worked MCQs
Five MCQs that capture the high-yield testing patterns for this chapter. Read the explanation even when you get the answer right — it's where the deeper concept lives.
Q1. A bright-line emission spectrum is produced by:
Only free atoms in a low-pressure gas give discrete lines. Hot dense sources (filament, molten iron) give a continuous spectrum; a cool gas in front of a continuous source gives a dark-line absorption spectrum.
Q2. Atomic spectra consist of sharp discrete lines rather than a continuous band because:
Only certain energy differences Ei − Ef are available, so only certain photon frequencies can be emitted or absorbed. Discrete energy levels are the whole explanation of a line spectrum.
Q3. An atom emits a photon when it falls from an energy level of −3.4 eV to a level of −13.6 eV. The energy of the emitted photon is:
hf = Ei − Ef = (−3.4) − (−13.6) = 10.2 eV. Subtract, never add, the two level energies — adding gives the 17.0 eV distractor.
Q4. A dark-line absorption spectrum of an element occurs at:
The same pair of energy levels is involved whether the atom absorbs or emits, so the wavelengths coincide. This is why the line spectrum works as a chemical fingerprint — e.g. the Fraunhofer lines in sunlight.
Q5. The wavelength of a spectral line produced by a transition of energy 2.0 eV is approximately:
Using hc = 1240 eV nm, λ = 1240/E = 1240/2.0 = 620 nm, in the orange-red part of the visible spectrum. Larger energy gaps give shorter wavelengths.
Quick Recap
- Continuous spectrum = all wavelengths, from a hot dense source; line spectrum = discrete wavelengths, from free atoms in a gas.
- Emission spectrum: bright lines on a dark background. Absorption spectrum: dark lines on a bright background.
- Both occur at the same wavelengths for a given element — a chemical fingerprint.
- Atoms have discrete energy levels; a transition emits or absorbs one photon of energy hf = Ei − Ef.
- Only certain energy differences exist, so only certain wavelengths appear — hence sharp lines.
- Useful: λ (nm) = 1240 / E (eV).