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Atomic Spectra

When an atom emits or absorbs light it does so only at sharply defined wavelengths — producing a line spectrum rather than a continuous one. Niels Bohr's 1913 model explained the hydrogen line spectrum as transitions between quantised orbits. The PMDC MDCAT 2026 syllabus places Atomic Spectra in the modern-physics block; expect 1-2 high-yield MCQs from this chapter.

PMC Table of Specifications. The single subtopic listed here is Atomic Spectra / Line Spectrum, but the exam expects a deep dive: Bohr's postulates, the hydrogen line series, the Rydberg equation, ionisation energy, and X-ray production.

Atomic Spectra and Line Spectrum

A spectrum is the range of EM wavelengths emitted or absorbed by a substance. Hot solids emit a continuous spectrum; rarefied gases excited by an electric discharge emit a line emission spectrum — a set of bright lines on a dark background. A cool gas placed between a continuous source and a spectrometer absorbs the same wavelengths, producing a line absorption spectrum (dark lines on bright background, e.g. Fraunhofer lines in sunlight).

Bohr's model of the hydrogen atom

Bohr combined Rutherford's nuclear atom with Planck's quantum hypothesis. His three key postulates are:

Bohr radii and energies (hydrogen)

The radius of the n-th orbit is rn = n2 a0, where a0 = 0.529 Å is the Bohr radius (the n = 1 orbit). The total energy of the electron in the n-th level is

En = −13.6 / n2 eV

Negative sign → the electron is bound. As n → ∞, E → 0 (free electron). The ground state (n = 1) lies at −13.6 eV.

Hydrogen line series and the Rydberg equation

Each transition n2 → n1 emits a photon whose wavenumber is given by the Rydberg formula:

1/λ = R (1/n12 − 1/n22)

with R = 1.097 × 107 m−1 (Rydberg constant) and n2 > n1.

Hydrogen line series — lower level, region, key wavelengths
SeriesTransitions n →Region of EM spectrumNotable lines
Lymanany → 1UltravioletHighest-energy series
Balmerany → 2VisibleHα 656 nm (red), Hβ 486 nm (cyan), Hγ 434 nm (blue)
Paschenany → 3Near infrared
Brackettany → 4Infrared
Pfundany → 5Far infraredLowest-energy series
Hydrogen energy levels (En = −13.6 / n² eV)
nEnergy (eV)Orbit radiusStatus
1−13.6a0 = 0.529 ÅGround state
2−3.404 a01st excited
3−1.519 a02nd excited
4−0.8516 a03rd excited
0Ionised (free electron)
Mnemonic. "Little Boys Play Basketball Poorly" — Lyman, Balmer, Paschen, Brackett, Pfund. n1 = 1, 2, 3, 4, 5 respectively. Only Balmer is visible to the human eye.

Ionisation energy of hydrogen

The energy needed to remove the electron from the ground state (n = 1) to n = ∞ is

Eion = E − E1 = 0 − (−13.6) = 13.6 eV.

This is the standard ionisation energy of atomic hydrogen and a fundamental constant used throughout modern physics MCQs.

Emission vs absorption spectra

X-ray production

X-rays are produced when high-speed electrons are decelerated on a metal target inside an evacuated tube. The output has two components:

Common trap. Examiners often switch the n1 and n2 in the Rydberg equation. Always put the lower level as n1 in the formula 1/λ = R(1/n12 − 1/n22) so that 1/λ comes out positive.

Worked MCQs

Five MCQs that capture the high-yield testing patterns for this chapter. Read the explanation even when you get the answer right — it's where the deeper concept lives.

Q1. The ionisation energy of a hydrogen atom in its ground state is:

  • 3.4 eV
  • 13.6 eV
  • 27.2 eV
  • 1.51 eV

E1 = −13.6 eV; ionisation energy = E − E1 = 13.6 eV. The other values correspond to higher levels: E2 = −3.4 eV, E3 = −1.51 eV.

Q2. Spectral lines of the Balmer series of hydrogen lie in which region of the spectrum?

  • Ultraviolet
  • Visible
  • Infrared
  • Microwave

All Balmer transitions terminate at n = 2 and lie in the visible (Hα 656 nm red, Hβ 486 nm). The Lyman series is UV; Paschen, Brackett and Pfund all lie in the IR region.

Q3. According to Bohr's model, the angular momentum of an electron in the n-th orbit is:

  • nh
  • nh/(2π)
  • n2h/(2π)
  • 2πn/h

Bohr's quantisation condition: mvr = nh/(2π) = nℏ. This is the cornerstone postulate that produces the discrete orbits and energies.

Q4. The minimum wavelength of X-rays produced in a Coolidge tube depends on:

  • Filament current
  • Accelerating potential V
  • Target material only
  • Pressure inside the tube

λmin = hc/(eV). Higher accelerating voltage gives more energetic electrons and shorter minimum wavelength. The target material affects the characteristic peaks, not λmin.

Q5. The radius of the n-th Bohr orbit in a hydrogen atom is proportional to:

  • n
  • n2
  • 1/n
  • 1/n2

rn = n2 a0 with a0 = 0.529 Å. Energy varies as 1/n2; orbital radius varies as n2. So n = 2 is four times bigger than n = 1, etc.

Quick Recap

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