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Dawn of Modern Physics

By 1900 classical physics could not explain blackbody radiation, the photoelectric effect, or atomic stability. The breakthroughs of Planck, Einstein, Bohr, de Broglie, and Compton ushered in modern physics. The PMDC MDCAT 2026 syllabus packs all this into a single subtopic — "Quantum Theory and Radiation" — that yields a steady stream of MCQs every year.

PMC Table of Specifications. Quantum Theory and Radiation is the single listed subtopic, but it bundles Planck's hypothesis, the photoelectric effect, Compton effect, de Broglie waves, blackbody radiation, and the Rutherford/Bohr atomic models.

Quantum Theory and Radiation

The classical Rayleigh-Jeans law predicted infinite radiation at short wavelengths — the so-called "ultraviolet catastrophe." Experiments showed instead a peak at a finite wavelength.

Blackbody radiation

Planck's quantum hypothesis (1900)

To fit the blackbody curve, Planck proposed that radiation is emitted/absorbed in discrete packets called quanta:

E = hf = hc/λ

where h = 6.626 × 10−34 J s is Planck's constant. This was the foundational idea that begins quantum mechanics.

Photoelectric effect

When light of sufficiently high frequency strikes a metal surface, electrons are ejected immediately. Classical wave theory could not explain four observations:

Einstein (1905) explained the effect using Planck's quanta — light behaves as discrete photons of energy hf. Each photon ejects one electron:

hf = φ + KEmax

where φ = h f0 is the work function of the metal (minimum energy to free an electron). Therefore KEmax = hf − φ.

Experimentally, KEmax is measured by applying a reverse stopping potential Vs until the photocurrent just falls to zero: eVs = KEmax.

Common trap. Increasing the intensity of light increases the number of photoelectrons (current) but not their kinetic energy. To raise KEmax you must raise the frequency. This is the most-tested fact in modern physics.

Compton effect

When X-ray photons scatter off loosely bound electrons, the scattered radiation has a longer wavelength than the incident. This proves that photons carry both energy and momentum.

Δλ = λ' − λ = (h/mec)(1 − cosθ)

The factor h/(mec) = 2.43 × 10−12 m is the Compton wavelength of the electron. Δλ is independent of the incident wavelength — it depends only on the scattering angle.

Photoelectric effect vs Compton effect vs Pair production
PropertyPhotoelectricComptonPair production
Photon energy rangeUV / visible (eV)X-ray (~keV)> 1.022 MeV (gamma)
Target electronTightly bound (in metal)Loosely bound / freeNucleus (needs electric field)
Photon fateAbsorbed entirelyScattered with lower energy (longer λ)Disappears, becomes e + e+
OutcomeElectron ejected from metalScattered photon + recoiling electronElectron-positron pair
Key equationhf = φ + KEmaxΔλ = (h/mec)(1 − cosθ)hν ≥ 2mec² (= 1.022 MeV)
Thresholdf ≥ f0 = φ/hNone (any X-ray scatters)1.022 MeV minimum photon energy
DemonstratesParticle nature of light, quantisationPhoton momentum p = h/λMass-energy equivalence E = mc²

de Broglie wavelength — matter waves

If light has particle properties, particles should have wave properties. Louis de Broglie (1924) proposed:

λ = h/p = h/(mv)

This was confirmed by the Davisson-Germer electron diffraction experiment (1927). Macroscopic objects have unmeasurably tiny λ (e.g. 10−34 m for a cricket ball); only microscopic particles show wave behaviour.

Wave-particle duality

Light and matter both behave sometimes as waves (interference, diffraction) and sometimes as particles (photoelectric effect, Compton scattering). The two pictures are complementary, not contradictory — the experiment chooses which face appears.

Atomic models — Rutherford to Bohr

Mnemonic for the constants. Memorise just two numbers and derive the rest: h = 6.626 × 10−34 J s and 1 eV = 1.602 × 10−19 J. From these you can convert any photon energy from joules to eV (divide by 1.6 × 10−19) and back.

Worked MCQs

Five MCQs that capture the high-yield testing patterns for this chapter. Read the explanation even when you get the answer right — it's where the deeper concept lives.

Q1. The maximum kinetic energy of photoelectrons depends on:

  • Intensity of incident light only
  • Frequency of incident light and work function
  • Intensity and angle of incidence
  • Surface area of the metal only

From Einstein's equation KEmax = hf − φ. Intensity changes the number of photoelectrons (current), not their energy. The threshold frequency f0 = φ/h is set by the metal.

Q2. The de Broglie wavelength of a particle of mass m and kinetic energy E is:

  • h/(mE)
  • h/√(2mE)
  • hE/m
  • √(2hE/m)

For a non-relativistic particle p = √(2mE), so λ = h/p = h/√(2mE). This is the standard form used in MCQs about electrons accelerated through a potential V (where E = eV).

Q3. Wien's displacement law states that as the temperature of a blackbody rises:

  • Total radiated power decreases
  • Peak wavelength stays constant
  • Peak wavelength becomes shorter
  • The body becomes a perfect reflector

λmax T = b. As T ↑, λmax ↓ — that's why a heated iron rod glows red, then orange, then white as it gets hotter. Total power E = σT4 rises sharply as well.

Q4. The Compton shift Δλ in a scattering experiment depends on:

  • Wavelength of incident X-rays
  • Scattering angle θ
  • Intensity of incident beam
  • Material of the scatterer

Δλ = (h/mec)(1 − cosθ). It is zero at θ = 0°, maximum at θ = 180°, and independent of incident λ or intensity. This was the strongest evidence that photons carry momentum p = h/λ.

Q5. The work function of a metal is 2 eV. The threshold wavelength is approximately:

  • 310 nm
  • 620 nm
  • 1240 nm
  • 62 nm

A useful conversion: hc = 1240 eV nm. Threshold wavelength λ0 = hc/φ = 1240/2 = 620 nm (orange light). For most common metals φ falls in 2-5 eV, so threshold is in the visible-UV region.

Quick Recap

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