Electrostatics
Electrostatics deals with charges at rest and the forces, fields, potentials, and energy associated with them. The PMDC MDCAT 2026 syllabus is dense in this chapter — from Coulomb's law and field calculations for points/sheets, to capacitors and RC charging/discharging. Expect 2-3 MCQs.
Coulomb's Law
Two point charges q1 and q2 separated by distance r exert on each other a force directed along the line joining them:
F = k q1q2 / r2
where k = 1 / (4πε0) ≈ 9 × 109 N m2 C−2 in vacuum, and ε0 = 8.85 × 10−12 C2 N−1 m−2.
- Like charges repel; unlike charges attract.
- The force obeys Newton's third law (equal and opposite).
- In a medium of relative permittivity εr, divide the vacuum force by εr.
- The principle of superposition: net force = vector sum of individual Coulomb forces.
Electric Field
An electric field at a point is the force per unit positive test charge placed there:
E = F / q
SI unit: N C−1 = V m−1. E is a vector quantity in the direction of force on a positive test charge.
Electric Field Intensity (Point Charge)
The field at distance r from a point charge Q in vacuum is
E = kQ / r2
Direction: radially outward for +Q, inward for −Q.
| Source | Formula for E | Direction / notes |
|---|---|---|
| Point charge Q (vacuum) | E = kQ/r² = Q/(4πε0r²) | Radial, ∝ 1/r² |
| Long charged rod (linear density λ) | E = λ/(2πε0r) | Radial, ∝ 1/r |
| Infinite charged sheet (σ) | E = σ/(2ε0) | Perpendicular to sheet, independent of distance |
| Parallel-plate capacitor (between) | E = σ/ε0 = V/d | Uniform between plates; zero outside |
| Inside a conductor (electrostatic) | E = 0 | Charge resides on outer surface (Faraday cage) |
| At centre of a uniformly charged sphere | E = 0 | Symmetry → net field cancels |
| Outside uniformly charged sphere | E = kQ/r² | Behaves like point charge at centre |
Under electrostatic equilibrium, the electric field inside a conductor is zero. Any excess charge resides on the outer surface; the conductor itself is at one constant potential (an equipotential volume). This is the principle behind electrostatic shielding.
Electric Field (Infinite Sheet)
A uniformly charged infinite plane of surface charge density σ (C m−2) produces a uniform field perpendicular to the sheet on either side:
E = σ / (2ε0)
The field is independent of distance from the sheet (within the infinite-sheet idealisation).
Two parallel sheets — the parallel-plate capacitor
Two infinite sheets carrying opposite charge densities ±σ produce a uniform field between the plates and zero field outside:
Ebetween = σ / ε0
This is twice the single-sheet result — the contributions from the two plates add up between, cancel outside.
Electric Field Lines
Field lines (Faraday's lines of force) provide a visual map of an electric field. Properties to remember:
- They begin on positive charges and end on negative charges (or run to infinity).
- The tangent at any point gives the direction of E there.
- Density of lines (lines per unit perpendicular area) is proportional to the magnitude of E.
- Two field lines never cross — the field has a unique direction at every point.
- Field lines are perpendicular to a conductor's surface in equilibrium.
Electric Potential Energy and Potential
The work done by an external agent in bringing a positive test charge q from infinity to a point against the field equals the electric potential energy U at that point.
Electric potential
V = U / q = W / q
Electric potential is potential energy per unit charge. SI unit: volt (V) = J C−1. It is a scalar — no direction, only sign.
Potential due to a point charge
V = kQ / r
(Reference: V = 0 at infinity.) Note V ∝ 1/r, while E ∝ 1/r2.
Potential energy of a charge pair
U = k q1q2 / r = q2 V1
Positive U → like charges (repulsive system). Negative U → unlike charges (bound system).
Relation to field
For a uniform field, V = E d (where d is distance along the field). In general, E = −dV/dx — the field points "downhill" in potential.
Charging and Discharging Capacitor
A capacitor stores charge. For any capacitor: C = Q / V (units: farad, F). For a parallel-plate capacitor in vacuum:
C = ε0 A / d
Inserting a dielectric of permittivity εr multiplies C by εr.
Combinations
- Series: 1/Cs = 1/C1 + 1/C2 + ... ; same charge on each, voltages add.
- Parallel: Cp = C1 + C2 + ... ; same voltage across each, charges add.
- Energy stored: U = ½ CV2 = ½ QV = Q2/(2C).
Charging through a resistor (RC circuit)
When a capacitor is charged through a resistor R from a battery of EMF V0:
V(t) = V0 (1 − e−t/τ)
The charge on the capacitor builds up exponentially. The time constant
τ = RC
is the time taken for the capacitor to reach 63% of its final voltage. After 5τ it is essentially fully charged.
Discharging
When a charged capacitor discharges through a resistor:
V(t) = V0 e−t/τ
Voltage drops to 37% of its initial value after one time constant.
Worked MCQs
Five MCQs that capture the high-yield testing patterns for this chapter. Read the explanation even when you get the answer right — it's where the deeper concept lives.
Q1. The Coulomb force between two point charges, when the distance between them is doubled, becomes:
F ∝ 1/r2. Doubling r quarters the force. The same inverse-square dependence governs gravitation and the electric field of a point charge.
Q2. The electric field inside a conductor in electrostatic equilibrium is:
If E were non-zero inside a conductor, free electrons would accelerate — not "equilibrium." Excess charge sits on the outer surface, leaving zero field inside. This is why a Faraday cage shields the interior from external fields.
Q3. A 10 µF capacitor is charged through a 200 kΩ resistor. The time constant of the circuit is:
τ = RC = (2 × 105) × (10−5) = 2 s. After 2 s the capacitor reaches 63% of the supply voltage; after ~10 s (5τ) it is essentially fully charged.
Q4. The electric field due to an infinite plane sheet of charge with surface density σ is:
Single infinite sheet: E = σ/(2ε0), independent of distance. Between two parallel oppositely charged sheets the fields add and E = σ/ε0 (and zero outside) — that's the parallel-plate capacitor.
Q5. The energy stored in a capacitor of capacitance C charged to potential V is:
Energy U = ½ CV2 = ½ QV = Q2/(2C). The factor of ½ arises because the voltage rises from 0 to V as charge accumulates — the work integral gives half of QV.
Quick Recap
- Coulomb: F = kq1q2/r2; k = 9 × 109 N m2 C−2.
- Field of a point charge: E = kQ/r2; potential: V = kQ/r.
- Inside a conductor in equilibrium: E = 0.
- Infinite sheet: E = σ/(2ε0); parallel-plate capacitor inside: E = σ/ε0.
- Field lines: + to −, never cross, density = magnitude.
- Potential energy: U = kq1q2/r; V = U/q.
- Capacitor: C = Q/V; parallel plate C = ε0A/d; energy U = ½CV2.
- Combinations: series 1/Cs = Σ1/C; parallel Cp = ΣC.
- RC circuit: τ = RC. Charging V = V0(1 − e−t/τ); discharging V = V0e−t/τ.