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Vectors and Equilibrium

Vectors are the mathematical foundation of mechanics. The PMDC MDCAT 2026 syllabus lists exactly three subtopics here: adding vectors via rectangular components, the scalar (dot) product, and the vector (cross) product. Expect 1-2 MCQs from this chapter, often as part of a hybrid mechanics problem.

PMC Table of Specifications. Three subtopics — Vector Addition by Rectangular Components, Scalar (dot) Product, and Vector (cross) Product — with applications across all of mechanics.

Addition of Vectors (Rectangular Components)

A vector A in 2-D can be resolved into perpendicular (rectangular) components along x and y axes:

A = Axî + Ayĵ

where î, ĵ, k̂ are the unit vectors along x, y, z. The components are:

Conversely, given the components, the magnitude and direction of A are:

Adding two vectors

To add A and B by components: split each into x and y components, add the components separately, then re-combine:

Memory aid. "Cosine for the side along the line, sine for across." Ax = A cosθ (along the reference x-axis), Ay = A sinθ (perpendicular to it).

Scalar Product

The scalar (dot) product of two vectors A and B is a scalar quantity defined by:

A·B = |A||B|cosθ

where θ is the angle between A and B. In component form:

A·B = AxBx + AyBy + AzBz

Properties

Physical examples

Vector Product

The vector (cross) product of A and B is a vector defined by:

A × B = |A||B|sinθ·n̂

where n̂ is a unit vector perpendicular to the plane containing A and B, with direction given by the right-hand rule: curl the fingers of the right hand from A to B; the thumb points in the direction of A × B.

Properties

Common trap. The cross product is not commutative. A × B = −B × A. Many students lose marks by forgetting this and switching the order of operands during simplification.

Physical examples

Determinant form

For A = Axî + Ayĵ + Azk̂ and B = Bxî + Byĵ + Bzk̂:

A × B = (AyBz − AzBy)î + (AzBx − AxBz)ĵ + (AxBy − AyBx)k̂

Scalar (dot) vs Vector (cross) product
PropertyScalar (dot) product A · BVector (cross) product A × B
ResultScalarVector
Definition|A| |B| cosθ|A| |B| sinθ · n̂
Maximum whenθ = 0° → |A||B|θ = 90° → |A||B|
Zero whenθ = 90° (perpendicular)θ = 0° or 180° (parallel / antiparallel)
Commutative?Yes — A · B = B · ANo — A × B = −(B × A)
Self-productA · A = |A|²A × A = 0
Geometric meaningProjection of one onto the otherArea of parallelogram with sides A, B
Physics examplesWork W = F · d, Power P = F · v, Flux Φ = B · ATorque τ = r × F, Angular momentum L = r × p, F = qv × B

Worked MCQs

Five MCQs that capture the high-yield testing patterns for this chapter.

Q1. The magnitude of the resultant of two perpendicular vectors of magnitudes 3 and 4 is:

  • 1
  • 3.5
  • 5
  • 7

|R| = √(3² + 4²) = √25 = 5. Classic 3-4-5 triangle.

Q2. If A·B = 0 and neither A nor B is zero, then the angle between them is:

  • 45°
  • 90°
  • 180°

A·B = |A||B|cosθ. Zero requires cosθ = 0, i.e. θ = 90° (perpendicular vectors).

Q3. The vector product î × ĵ equals:

  • 0
  • −k̂
  • î + ĵ

Cyclic order in right-handed system: î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ. Reverse order picks up a minus sign.

Q4. The torque produced by a force F applied at a position vector r relative to a pivot is:

  • r·F
  • r × F
  • F × r
  • |r||F|cosθ

Torque is a vector quantity defined as τ = r × F (cross product). Note that F × r would give the wrong sign.

Q5. If A = 2î + 3ĵ and B = 4î − ĵ, then A·B equals:

  • 11
  • −3
  • 5
  • 8

A·B = (2)(4) + (3)(−1) = 8 − 3 = 5.

Quick Recap

Test yourself. Take a timed Vectors quiz or browse all Physics MCQs to lock these concepts in.