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Vectors and Equilibrium

Vectors and Equilibrium is the mathematical foundation of mechanics. The PMDC MDCAT 2026 syllabus expects fluency in adding vectors via rectangular components, computing scalar (dot) products, and computing vector (cross) products. Expect 1-2 MCQs from this chapter, often as part of a hybrid mechanics problem.

PMC Table of Specifications. Three subtopics — Vector Addition by Rectangular Components, Scalar (dot) Product, and Vector (cross) Product — with applications across all of mechanics.

Addition of Vectors (Rectangular Components)

A vector A in 2-D can be resolved into perpendicular (rectangular) components along x and y axes:

A = Axî + Ayĵ

where î, ĵ, k̂ are the unit vectors along x, y, z. The components are:

Conversely, given the components, the magnitude and direction of A are:

Adding two vectors

To add A and B by components: split each into x and y components, add the components separately, then re-combine:

Memory aid. "Cosine for the side along the line, sine for across." Ax = A cosθ (along the reference x-axis), Ay = A sinθ (perpendicular to it).

Scalar Product

The scalar (dot) product of two vectors A and B is a scalar quantity defined by:

A·B = |A||B|cosθ

where θ is the angle between A and B. In component form:

A·B = AxBx + AyBy + AzBz

Properties

Physical examples

Vector Product

The vector (cross) product of A and B is a vector defined by:

A × B = |A||B|sinθ·n̂

where n̂ is a unit vector perpendicular to the plane containing A and B, with direction given by the right-hand rule: curl the fingers of the right hand from A to B; the thumb points in the direction of A × B.

Properties

Common trap. The cross product is not commutative. A × B = −B × A. Many students lose marks by forgetting this and switching the order of operands during simplification.

Physical examples

Determinant form

For A = Axî + Ayĵ + Azk̂ and B = Bxî + Byĵ + Bzk̂:

A × B = (AyBz − AzBy)î + (AzBx − AxBz)ĵ + (AxBy − AyBx)k̂

Scalar (dot) vs Vector (cross) product
PropertyScalar (dot) product A · BVector (cross) product A × B
ResultScalarVector
Definition|A| |B| cosθ|A| |B| sinθ · n̂
Maximum whenθ = 0° → |A||B|θ = 90° → |A||B|
Zero whenθ = 90° (perpendicular)θ = 0° or 180° (parallel / antiparallel)
Commutative?Yes — A · B = B · ANo — A × B = −(B × A)
Self-productA · A = |A|²A × A = 0
Geometric meaningProjection of one onto the otherArea of parallelogram with sides A, B
Physics examplesWork W = F · d, Power P = F · v, Flux Φ = B · ATorque τ = r × F, Angular momentum L = r × p, F = qv × B

Equilibrium of Forces

A body is in equilibrium when its state of rest or uniform motion is unchanged. Two conditions must hold:

First condition (translational equilibrium)
The vector sum of all forces acting on the body is zero: ΣF = 0. Equivalent: ΣFx = 0 and ΣFy = 0.
Second condition (rotational equilibrium)
The vector sum of all torques about any point is zero: Στ = 0.

Both conditions together → complete equilibrium. A book on a table satisfies the first; a balanced see-saw satisfies both.

Three coplanar forces in equilibrium can be drawn head-to-tail to form a closed triangle — this is the basis of the triangle / Lami's theorem: F1/sinα = F2/sinβ = F3/sinγ.

Worked MCQs

Five MCQs that capture the high-yield testing patterns for this chapter.

Q1. The magnitude of the resultant of two perpendicular vectors of magnitudes 3 and 4 is:

  • 1
  • 3.5
  • 5
  • 7

|R| = √(3² + 4²) = √25 = 5. Classic 3-4-5 triangle.

Q2. If A·B = 0 and neither A nor B is zero, then the angle between them is:

  • 45°
  • 90°
  • 180°

A·B = |A||B|cosθ. Zero requires cosθ = 0, i.e. θ = 90° (perpendicular vectors).

Q3. The vector product î × ĵ equals:

  • 0
  • −k̂
  • î + ĵ

Cyclic order in right-handed system: î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ. Reverse order picks up a minus sign.

Q4. The torque produced by a force F applied at a position vector r relative to a pivot is:

  • r·F
  • r × F
  • F × r
  • |r||F|cosθ

Torque is a vector quantity defined as τ = r × F (cross product). Note that F × r would give the wrong sign.

Q5. If A = 2î + 3ĵ and B = 4î − ĵ, then A·B equals:

  • 11
  • −3
  • 5
  • 8

A·B = (2)(4) + (3)(−1) = 8 − 3 = 5.

Quick Recap

Test yourself. Take a timed Vectors quiz or browse all Physics MCQs to lock these concepts in.