Vectors and Equilibrium
Vectors and Equilibrium is the mathematical foundation of mechanics. The PMDC MDCAT 2026 syllabus expects fluency in adding vectors via rectangular components, computing scalar (dot) products, and computing vector (cross) products. Expect 1-2 MCQs from this chapter, often as part of a hybrid mechanics problem.
Addition of Vectors (Rectangular Components)
A vector A in 2-D can be resolved into perpendicular (rectangular) components along x and y axes:
A = Axî + Ayĵ
where î, ĵ, k̂ are the unit vectors along x, y, z. The components are:
- Ax = A·cosθ
- Ay = A·sinθ
Conversely, given the components, the magnitude and direction of A are:
- |A| = √(Ax² + Ay²)
- tanθ = Ay/Ax
Adding two vectors
To add A and B by components: split each into x and y components, add the components separately, then re-combine:
- Rx = Ax + Bx
- Ry = Ay + By
- |R| = √(Rx² + Ry²)
- tanφ = Ry/Rx
Scalar Product
The scalar (dot) product of two vectors A and B is a scalar quantity defined by:
A·B = |A||B|cosθ
where θ is the angle between A and B. In component form:
A·B = AxBx + AyBy + AzBz
Properties
- Commutative: A·B = B·A.
- Distributive: A·(B + C) = A·B + A·C.
- Self-product: A·A = |A|².
- If A ⊥ B then A·B = 0.
- If A ∥ B then A·B = |A||B|.
- Unit vectors: î·î = ĵ·ĵ = k̂·k̂ = 1; î·ĵ = ĵ·k̂ = k̂·î = 0.
Physical examples
- Work done by a constant force: W = F·d·cosθ = F·d (dot product).
- Power: P = F·v.
- Magnetic flux: Φ = B·A.
Vector Product
The vector (cross) product of A and B is a vector defined by:
A × B = |A||B|sinθ·n̂
where n̂ is a unit vector perpendicular to the plane containing A and B, with direction given by the right-hand rule: curl the fingers of the right hand from A to B; the thumb points in the direction of A × B.
Properties
- Anti-commutative: A × B = −(B × A).
- Distributive: A × (B + C) = A × B + A × C.
- Self-product: A × A = 0.
- If A ∥ B then A × B = 0.
- If A ⊥ B then |A × B| = |A||B|.
- Unit vectors (cyclic order): î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ. Reverse order gives a minus sign.
Physical examples
- Torque: τ = r × F.
- Angular momentum: L = r × p.
- Magnetic force on a moving charge: F = qv × B.
- Magnitude of A × B = area of the parallelogram with sides A and B.
Determinant form
For A = Axî + Ayĵ + Azk̂ and B = Bxî + Byĵ + Bzk̂:
A × B = (AyBz − AzBy)î + (AzBx − AxBz)ĵ + (AxBy − AyBx)k̂
| Property | Scalar (dot) product A · B | Vector (cross) product A × B |
|---|---|---|
| Result | Scalar | Vector |
| Definition | |A| |B| cosθ | |A| |B| sinθ · n̂ |
| Maximum when | θ = 0° → |A||B| | θ = 90° → |A||B| |
| Zero when | θ = 90° (perpendicular) | θ = 0° or 180° (parallel / antiparallel) |
| Commutative? | Yes — A · B = B · A | No — A × B = −(B × A) |
| Self-product | A · A = |A|² | A × A = 0 |
| Geometric meaning | Projection of one onto the other | Area of parallelogram with sides A, B |
| Physics examples | Work W = F · d, Power P = F · v, Flux Φ = B · A | Torque τ = r × F, Angular momentum L = r × p, F = qv × B |
Equilibrium of Forces
A body is in equilibrium when its state of rest or uniform motion is unchanged. Two conditions must hold:
- First condition (translational equilibrium)
- The vector sum of all forces acting on the body is zero: ΣF = 0. Equivalent: ΣFx = 0 and ΣFy = 0.
- Second condition (rotational equilibrium)
- The vector sum of all torques about any point is zero: Στ = 0.
Both conditions together → complete equilibrium. A book on a table satisfies the first; a balanced see-saw satisfies both.
Three coplanar forces in equilibrium can be drawn head-to-tail to form a closed triangle — this is the basis of the triangle / Lami's theorem: F1/sinα = F2/sinβ = F3/sinγ.
Worked MCQs
Five MCQs that capture the high-yield testing patterns for this chapter.
Q1. The magnitude of the resultant of two perpendicular vectors of magnitudes 3 and 4 is:
|R| = √(3² + 4²) = √25 = 5. Classic 3-4-5 triangle.
Q2. If A·B = 0 and neither A nor B is zero, then the angle between them is:
A·B = |A||B|cosθ. Zero requires cosθ = 0, i.e. θ = 90° (perpendicular vectors).
Q3. The vector product î × ĵ equals:
Cyclic order in right-handed system: î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ. Reverse order picks up a minus sign.
Q4. The torque produced by a force F applied at a position vector r relative to a pivot is:
Torque is a vector quantity defined as τ = r × F (cross product). Note that F × r would give the wrong sign.
Q5. If A = 2î + 3ĵ and B = 4î − ĵ, then A·B equals:
A·B = (2)(4) + (3)(−1) = 8 − 3 = 5.
Quick Recap
- A = Axî + Ayĵ; |A| = √(Ax² + Ay²); tanθ = Ay/Ax.
- Add by components: Rx = ΣAx, Ry = ΣAy.
- A·B = |A||B|cosθ = AxBx + AyBy; commutative.
- A × B = |A||B|sinθ·n̂; anti-commutative.
- î×ĵ=k̂, ĵ×k̂=î, k̂×î=ĵ (cyclic).
- Work = F·d (dot); Torque = r × F (cross).